X^2+6x-882=0

Solution for X^2+6x-882=0 equation:

X^2+6X-882=0

a = 1; b = 6; c = -882;
Δ = b2-4ac
Δ = 62-4·1·(-882)
Δ = 3564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3564}=\sqrt{324*11}=\sqrt{324}*\sqrt{11}=18\sqrt{11}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18\sqrt{11}}{2*1}=\frac{-6-18\sqrt{11}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18\sqrt{11}}{2*1}=\frac{-6+18\sqrt{11}}{2}
$